p.
400
[TEX: \frac{A \times V}{400} \times (V - v)^2 = h. p.]
in which A equals the area of blade in square feet, V and v velocities
of current and wheel periphery respectively, in feet per second. Thus,
for example, a wheel 10 feet in diameter with blades 6 feet long and 1
foot in width, running in a stream of 5 feet per second--assuming the
wheel to be giving as much power as will reduce its velocity to one half
that of the stream--the figures will be
6' x 5' 2
------- x 2.5 = 0.468
400
[TEX: \frac{6' \times 5'}{400} \times 2.5^2 = 0.468]
horse power of the wheel.
The total power of the stream due to the area of the blade equals the
Square of the velocity of the stream
------------------------------------ x
Twice gravity (64.33)
volume of water in cubic feet per second x 62.5 (weight of 1 C') = the
value or gross effect in pounds falling 1 foot per second. This sum
divided by 550 = horse power. Thus, as per last example,
2
5
------ x 30 x 62.5
64.33
---------------------- = 1.32 the horse power of the current
550
[TEX: \frac{\frac{5^2}{64.
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